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Himachal Pradesh mathematics - Practice Mock Test Set 11

1. Vijay invested 1380 at 5% per annum simple interest in a bank. What amount (in ₹) will he get after 5 years?
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2. Vijay invested 1380 at 5% per annum simple interest in a bank. What amount (in ₹) will he get after 5 years?
Mathematics 📄 JOA IT (2026)
3. Vijay invested 1380 at 5% per annum simple interest in a bank. What amount (in ₹) will he get after 5 years?
Mathematics 📄 JOA IT (2026)
4. Vijay invested 1380 at 5% per annum simple interest in a bank. What amount (in ₹) will he get after 5 years?
Mathematics 📄 JOA IT (2026)
5. Vijay invested 1380 at 5% per annum simple interest in a bank. What amount (in ₹) will he get after 5 years?
Mathematics 📄 JOA IT (2026)
6. Vijay invested 1380 at 5% per annum simple interest in a bank. What amount (in ₹) will he get after 5 years?
Mathematics 📄 JOA IT (2026)
7. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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8. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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9. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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10. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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11. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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12. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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13. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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14. A sum of 12,500 is invested for 3 years at 8% per annum. Find the difference between the compound interest (compounded annually) and the simple interest earned over the 3-year period.
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15. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
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16. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
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17. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
Mathematics 📄 JOA IT (2026)
18. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
Mathematics 📄 JOA IT (2026)
19. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
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20. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
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21. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
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22. Following bar graph shows the production of cars (in thousands) by a company over 5 years. If 20% of cars produced in 2024 were defective and 10% of cars produced in 2025 were defective, find the total number of non-defective cars produced in these two years.
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23. Simplify: $0.75 + \frac{3}{4}$
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24. Simplify: $0.75 + \frac{3}{4}$
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25. Simplify: $0.75 + \frac{3}{4}$
Mathematics 📄 JOA IT (2026)
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